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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Solve the following : Find the distance of the point (13, 13, – 13) from the plane 3x + 4y – 12z = 0.

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प्रश्न

Solve the following :

Find the distance of the point (13, 13, – 13) from the plane 3x + 4y – 12z = 0.

बेरीज
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उत्तर

The distance of the point (x1, y1, z1) from the plane ax + by + cz + d = 0 is `|(ax_1 + by_1 + cz_1 + d)/sqrt(a^2 + b^2 + c^2)|`

∴ the distance of the point (1, 1, – 1) from the plane 3x + 4y – 12z = 0 is `|(3(1) + 4(1 - 12(-1)))/sqrt(3^2 + 4^2 + (-12)^2)|`

= `|(3 + 4 + 12)/sqrt(9 + 16 + 144)|`

= `(19)/sqrt(169)`

= `(19)/(13)`

= 19units.

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पाठ 6: Line and Plane - Miscellaneous Exercise 6 B [पृष्ठ २२६]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Line and Plane
Miscellaneous Exercise 6 B | Q 18 | पृष्ठ २२६

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