Advertisements
Advertisements
प्रश्न
Solve the following equation and check your result:
`x = 4/5 (x + 10)`
Advertisements
उत्तर
`x = 4/5 (x + 10)`
Multiplying both sides by 5, we obtain
5x = 4(x + 10)
5x = 4x + 40
Transposing 4x to L.H.S, we obtain
5x − 4x = 40
x = 40
L.H.S = x = 40
R.H.S = `4/5 (x + 10`)
= `4/5 (40 + 10)`
=`4/5 xx 50`
= 40
L.H.S. = R.H.S.
Hence, the result obtained above is correct.
APPEARS IN
संबंधित प्रश्न
The base of an isosceles triangle is `4/3` cm. The perimeter of the triangle is `4 2/15` cm. What is the length of either of the remaining equal sides?
Solve the following equation and check your result:
`2y + 5/3 = 26/3 - y`
On subtracting 8 from x, the result is 2. The value of x is ______.
In the equation 3x – 3 = 9, transposing –3 to RHS, we get 3x = 9.
If `15/8 - 7x = 9`, then `-7x = 9 + 15/8`
Solve the following:
`8/x = 5/(x - 1)`
Solve the following:
`(2x - 1)/5 = (3x + 1)/3`
Solve the following:
`(9 - 3y)/(1 - 9y) = 8/5`
Solve the following:
`m - (m - 1)/2 = 1 - (m - 2)/3`
Solve the following:
0.16(5x – 2) = 0.4x + 7
