Advertisements
Advertisements
प्रश्न
Solve of the following equations, giving answer up to two decimal places.
3x2 – x – 7 =0
Advertisements
उत्तर
3x2 – x – 7 =0
Here a = 3, b = −1 and c = −7
`x = (-b +- sqrt((-1)^2 - 4(3)(-7)))/(2(3))`
`=> x = (1 +- sqrt85)/6 = (1 +- 9.22)/6`
`=> x = 10.22/6 and (-8.22)/6 = 1.70 and -1.37`
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`(x-1/2)^2=4`
Solve the following quadratic equation by factorization:
`(x-5)(x-6)=25/(24)^2`
Solve the following quadratic equations by factorization:
`a/(x-a)+b/(x-b)=(2c)/(x-c)`
Solve:
x(x + 1) + (x + 2)(x + 3) = 42
`8x^2-14x-15=0`
Solve for x:
4x2 + 4bx − (a2 − b2) = 0
Solve for x: `3x^2-2sqrt3x+2=0`
Write the condition to be satisfied for which equations ax2 + 2bx + c = 0 and \[b x^2 - 2\sqrt{ac}x + b = 0\] have equal roots.
Solve the equation using the factorisation method:
`(3x -2)/(2x -3) = (3x - 8)/(x + 4)`
If the sum of the roots of the quadratic equation ky2 – 11y + (k – 23) = 0 is `13/21` more than the product of the roots, then find the value of k.
