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प्रश्न
Solve for x:
`log_(sqrt(2)) x = 4`
बेरीज
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उत्तर
Given: `log_(sqrt(2)) x = 4`
Step-wise calculation:
Using the definition logb(x) = y ⇔ x = by, we get
`x = (sqrt(2))^4 xx (sqrt(2) = 2^(1/2))`
So `x = (2^(1/2))^4`
`x = 2^((1/2) xx 4)`
x = 22
x = 4
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Logarithms - Exercise 7A [पृष्ठ १४०]
