Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only
4x2 + 12x + 9 = 0
Advertisements
उत्तर
4x2 + 12x + 9 = 0
a = 4 ; b = 12 ; c = 9
D = b2 - 4ac
= (12)2 - 4(4)(9)
= 144 - 144
= 0
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(- 12 +- 0)/8`
x = `-3/2`
APPEARS IN
संबंधित प्रश्न
Determine the nature of the roots of the following quadratic equation:
(x – 2a)(x – 2b) = 4ab
Find the value of the discriminant in the following quadratic equation:
2x2 - 3x + 1 = O
Find the value of the discriminant in the following quadratic equation :
10 x - `1/x` = 3
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
9a2b2x2 - 48abc + 64c2d2 = 0, a ≠ 0, b ≠ 0
If one root of the equation x2+ px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots, the value of q is:
If α, β are roots of the equation x2 + 5x + 5 = 0, then equation whose roots are α + 1 and β + 1 is:
A quadratic equation with integral coefficient has integral roots. Justify your answer.
Every quadratic equation has at least two roots.
Find the roots of the quadratic equation by using the quadratic formula in the following:
`1/2x^2 - sqrt(11)x + 1 = 0`
Assertion (A): If one root of the quadratic equation 4x2 – 10x + (k – 4) = 0 is reciprocal of the other, then value of k is 8.
Reason (R): Roots of the quadratic equation x2 – x + 1 = 0 are real.
