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प्रश्न
Solve the following equation:
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उत्तर
\[2 \cos^2 x - 5 \cos x + 2 = 0\]
\[ \Rightarrow 2 \cos^2 x - 4 \cos x - \cos x + 2 = 0\]
\[ \Rightarrow 2 \cos x ( \cos x - 2) - 1 ( \cos x - 2) = 0\]
\[ \Rightarrow (\cos x - 2) ( 2 \cos\theta - 1) = 0\]
\[\therefore 2 \cos x - 1 = 0 \]
\[ \Rightarrow \cos x = \frac{1}{2} \]
\[ \Rightarrow \cos x = \cos \frac{\pi}{3} \]
\[ \Rightarrow x = 2n\pi \pm \frac{\pi}{3}, n \in Z\]
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