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​Solve the Following Determinant Equation: ∣ ∣ ∣ ∣ X + a X X X X + a X X X X + a ∣ ∣ ∣ ∣ = 0 , a ≠ 0

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प्रश्न

​Solve the following determinant equation:

\[\begin{vmatrix}x + a & x & x \\ x & x + a & x \\ x & x & x + a\end{vmatrix} = 0, a \neq 0\]

 

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उत्तर

\[\text{ Let }∆ = \begin{vmatrix}x + a & x & x \\ x & x + a & x \\ x & x & x + a\end{vmatrix}\] 

\[ = \begin{vmatrix}3x + a & x & x \\ 3x + a & x + a & x \\ 3x + a & x & x + a\end{vmatrix} \left[\text{ Applying }C_1 \text{ to }C_1 + C_2 + C_3 \right]\] 

\[ = \left( 3x + a \right)\begin{vmatrix}1 & x & x \\ 1 & x + a & x \\ 1 & x & x + a\end{vmatrix}\] 

\[ = \left( 3x + a \right)\begin{vmatrix}1 & x & x \\ 0 & a & 0 \\ 1 & x & x + a\end{vmatrix} \left[\text{ Applying }R_2 \text{ to }R_2 - R_1 \right]\] 

\[ = \left( 3x + a \right)\begin{vmatrix}1 & x & x \\ 0 & a & 0 \\ 0 & 0 & a\end{vmatrix} \left[\text{ Applying }R_3 \text{ to }R_3 - R_1 \right]\] 

\[ ∆ = \left( 3x + a \right)\left( a^2 - 0 \right) = 0\] 

\[x = \frac{- a}{3}\]

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पाठ 5: Determinants - Exercise 6.2 [पृष्ठ ६१]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 5 Determinants
Exercise 6.2 | Q 52.2 | पृष्ठ ६१

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