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प्रश्न
Solve each of the following systems of equations by the method of cross-multiplication
`x/a = y/b`
`ax + by = a^2 + b^2`
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उत्तर
`x/a = y/b`
``ax + by = a^2 + b^2`
Here `a_1 = 1/a, b_1 = (-1)/b, c_1 = 0`
`a_2 = a, b_2 = b,c_2 = -(a^2 + b^2)`
By cross multiplication, we get
`x/(-1/b(-(a^2 + b^2))-b(0)) = (-y)/(1/a(-(a^2 + b^2))-a(0)) = 1/(1/a (b) - a xx ((-1)/b))`
`x/((a^2 + b^2)/b) = y/((a^2 + b^2)/a) = 1/(b/a + a/b)`
`x = ((a^2 + b^2)/b)/(b/a + a/b) = ((a^2 +b^2)/b)/((b^2 + a^2)/(ab)) = a`
`y = ((a^2 + b^2)/a)/(b/a + a/b) = ((a^2 + b^2)/b)/((b^2+a^2)/(ab)) = b`
Solution is (a, b)
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