Advertisements
Advertisements
प्रश्न
Solve:
`1/(x + 1) - 2/(x + 2) = 3/(x + 3) - 4/(x + 4)`
Advertisements
उत्तर
`1/(x + 1) - 2/(x + 2) = 3/(x + 3) - 4/(x + 4)`
`=> (1(x + 2)-2(x + 1))/((x + 1)(x + 2)) = (3(x + 4)- 4(x + 3))/((x + 3)(x + 4))`
`=> (-x)/(x^2 + 3x + 2) = (-x)/(x^2 + 7x + 12)`
`=> -x[x^2 + 3x + 2 = x^2 + 7x + 12]`
`=> -x[-4x = 10]`
`=> x = 0` and `x = (-10)/4 = -2.5`
APPEARS IN
संबंधित प्रश्न
The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
Find the two consecutive natural numbers whose product is 20.
Factorise : m2 + 5m + 6.
Find the roots of the quadratic equation \[\sqrt{2}x^2 + 7x + 5\sqrt{2} = 0\].
If 1 is a root of the quadratic equation \[3 x^2 + ax - 2 = 0\] and the quadratic equation \[a( x^2 + 6x) - b = 0\] has equal roots, find the value of b.
If the equation 9x2 + 6kx + 4 = 0 has equal roots, then the roots are both equal to
The number of quadratic equations having real roots and which do not change by squaring their roots is
Solve the following equation: `10"x" - 1/"x" = 3`
Solve the following equation: `"a"/("x" - "a") + "b"/("x" - "b") = (2"c")/("x" - "c")`
Harish made a rectangular garden, with its length 5 metres more than its width. The next year, he increased the length by 3 metres and decreased the width by 2 metres. If the area of the second garden was 119 sq m, was the second garden larger or smaller ?
