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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Solve: 1+dydx=cosec(x+y); put x + y = u.

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प्रश्न

Solve:

`1 + (dy)/(dx) = cosec (x + y)`; put x + y = u.

बेरीज
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उत्तर

`1 + dy/dx = cosec (x + y)`    ...(i)

Put x + y = u

⇒ `1 + dy/dx = du/dx`

∴ 1 + `"dy"/("d"x)="du"/("d"x)`

Given differential equation (i) becomes

`(du)/dx` = cosec u

∴ `(du)/("cosec"  u) = dx`

`therefore int 1/("cosec"  u) du = int dx`

∴ ∫sin u du = ∫dx

∴ −cos u = x + c

∴ x + cos u + c = 0

∴ x + cos (x + y) + c = 0     ...(∵ x + y = u)

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