मराठी

Solid ammonium dichromate decomposes as: (NHA4)A2CrA2OA7⟶NA2+CrA2OA3+4HA2O If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of nitrogen formed. - Chemistry

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प्रश्न

Solid ammonium dichromate decomposes as:

\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]

If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of nitrogen formed.

संख्यात्मक
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उत्तर

1 mole of (NH4)2Cr2O7 contains nitrogen = 1 mole

∴ 0.25 mole of (NH4)2Cr2O7 contains nitrogen = 0.25 mole

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