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प्रश्न
`sin^-1 1/2-2sin^-1 1/sqrt2`
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उत्तर
`sin^-1 1/2-2sin^-1 1/sqrt2 =sin^-1 1/2-sin^-1 2xx1/sqrt2sqrt(1-(1/sqrt2)^2)`
`=sin^-1 1/2-sin^-1sqrt2xx1/sqrt2`
`=sin^-1 1/2-sin^-1 1`
`=sin^-1(sin pi/6)-sin^-1(sin pi/2)`
`=pi/6-pi/2`
`=-pi/3`
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