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प्रश्न
Simplify.
(3r − 2k)3 + (3r + 2k)3
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उत्तर
It is known that formula,
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a − b)3 = a3 − 3a2b + 3ab2 − b3
Given: (3r − 2k)3 + (3r + 2k)3
= (3r)3 − (2k)3 − 3 × (3r)2 × 2k + 3 × 3r × (2k)2 + (3r)3 + (2k)3 + 3 × (3r)2 × 2k + 3 × 3r + (2k)2
= 27 r3 − 8 k3 − 54 rk + 36 rk2 + 27 r3 + 8 k3 + 54 r2k + 36 rk2
= 54 r3 + 72 rk2
संबंधित प्रश्न
Expand.
(101)3
Find the cube of : 5a + 3b
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(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
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`x^2 + 1/x^2 = x^3 + 1/x^3 = x^4 + 1/x^4`
If a + b + c = 0; then show that a3 + b3 + c3 = 3abc.
If a + b = 5 and ab = 2, find a3 + b3.
Expand (52)3
