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प्रश्न
Simplify:
\[\left( 2^{- 1} + 3^{- 1} \right)^{- 1}\]
बेरीज
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उत्तर
\[\left( 2^{- 1} + 3^{- 1} \right)^{- 1} = \left( \frac{1}{2} + \frac{1}{3} \right)^{- 1} {\to (a}^{- 1} = 1/a) \]
\[ = \left( \frac{5}{6} \right)^{- 1} = \frac{6}{5} {\to (a}^{- 1} = 1/a)\]
\[ = \left( \frac{5}{6} \right)^{- 1} = \frac{6}{5} {\to (a}^{- 1} = 1/a)\]
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| x | 1x | 2x | 3x | 4x | 5x | 6x | 7x | 8x | 9x | 10x |
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| 3 | 1 | 8 | ||||||||
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| 5 | 1 | 32 | ||||||||
| 6 | 1 | 64 | ||||||||
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