Advertisements
Advertisements
प्रश्न
Show that the point (11, 2) is the centre of the circle passing through the points (1, 2), (3, −4) and (5, −6)
Advertisements
उत्तर

Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
OA = `sqrt((11 - 1)^2 + (2 - 2)^2`
= `sqrt(10^2 + 0^2)`
= `sqrt(100)`
= 10
OB = `sqrt((11 - 3)^2 + (2 + 4)^2`
= `sqrt(8^2 + 6^2)`
= `sqrt(64 + 36)`
= `sqrt(100)`
= 10
OC = `sqrt((11 - 5)^2 + (2 + 6)^2`
= `sqrt(6^2 + 8^2)`
= `sqrt(36 + 64)`
= `sqrt(100)`
= 10
OA = OB = OC = 10
O is the centre of the circle passing through A, B and C.
APPEARS IN
संबंधित प्रश्न
On a number line, co-ordinates of P, Q, R are 3, -5 and 6 respectively. State with reason whether the following statement is true or false.
d(P, Q) + d(Q, R) = d(P, R)
On a number line, the co-ordinates of P, Q, R are 3, -5 and 6 respectively. State with reason whether the following statement is true or false.
d(R, P) + d(P, Q) = d(R, Q)
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 4, 5
Find the distance between the following pair of points
(a, b) and (c, b)
Show that the following points taken in order to form an isosceles triangle
A(5, 4), B(2, 0), C(−2, 3)
Show that the following points taken in order to form an equilateral triangle
`"A"(sqrt(3), 2), "B"(0, 1), "C"(0, 3)`
Show that the following points taken in order to form the vertices of a parallelogram
A(−3, 1), B(−6, −7), C(3, −9) and D(6, −1)
The distance between the point (5, −1) and the origin is _________
Find the distance with the help of the number line given below.

d(K, O)
Find the distance with the help of the number line given below.

d(O, E)
