Advertisements
Advertisements
प्रश्न
Show that the point (11, 2) is the centre of the circle passing through the points (1, 2), (3, −4) and (5, −6)
Advertisements
उत्तर

Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
OA = `sqrt((11 - 1)^2 + (2 - 2)^2`
= `sqrt(10^2 + 0^2)`
= `sqrt(100)`
= 10
OB = `sqrt((11 - 3)^2 + (2 + 4)^2`
= `sqrt(8^2 + 6^2)`
= `sqrt(64 + 36)`
= `sqrt(100)`
= 10
OC = `sqrt((11 - 5)^2 + (2 + 6)^2`
= `sqrt(6^2 + 8^2)`
= `sqrt(36 + 64)`
= `sqrt(100)`
= 10
OA = OB = OC = 10
O is the centre of the circle passing through A, B and C.
APPEARS IN
संबंधित प्रश्न
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = 6, y = - 2
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = -4, y = -5
If P - Q - R and d(P, Q) = 2, d(P, R) = 10, then find d(Q, R).
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 25, - 47
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
80, - 85
Find the distance between the following pair of points
(1, 2) and (4, 3)
Verify that the following points taken in order to form the vertices of a rhombus
A(3, −2), B(7, 6), C(−1, 2) and D(−5, −6)
The abscissa of a point A is equal to its ordinate, and its distance from the point B(1, 3) is 10 units, What are the coordinates of A?
Find the distance with the help of the number line given below.

d(J, A)
Find the distance with the help of the number line given below.

d(P, J)
