Advertisements
Advertisements
प्रश्न
Show that the given points are collinear: (– 3, – 4), (7, 2) and (12, 5)
Advertisements
उत्तर
The vertices are A(– 3, – 4), B(7, 2) and C(12, 5)
Slope of a line = `(y_2 - y_1)/(x_2 - x_1)`
Slope of AB = `(2 + 4)/(7 + 3) = 6/10 = 3/5`
Slope of BC = `(5 - 2)/(12 - 7) = 3/5`
Slope of AB = Slope of BC = `3/5`
∴ The three points A, B, C are collinear.
APPEARS IN
संबंधित प्रश्न
What is the slope of a line whose inclination with positive direction of x-axis is 90°
What is the slope of a line whose inclination with positive direction of x-axis is 0°
What is the inclination of a line whose slope is 0
Find the slope of a line joining the points
`(5, sqrt(5))` with the origin
Find the slope of a line joining the points
(sin θ, – cos θ) and (– sin θ, cos θ)
If the three points (3, – 1), (a, 3) and (1, – 3) are collinear, find the value of a
The line through the points (– 2, a) and (9, 3) has slope `-1/2` Find the value of a.
The line through the points (– 2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x.
A quadrilateral has vertices at A(– 4, – 2), B(5, – 1), C(6, 5) and D(– 7, 6). Show that the mid-points of its sides form a parallelogram.
Without using distance formula, show that the points (−2, −1), (4, 0), (3, 3) and (−3, 2) are vertices of a parallelogram
