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प्रश्न
Show that the following numbers are irrational.
`6 + sqrt(2)`
संख्यात्मक
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उत्तर
Let us assume that `6+sqrt2 ` is rational. Then, there exist positive co-primes a and b such that
`6+sqrt2=a/b`
`sqrt2=a/b-6`
`sqrt2=(a-6b)/b`
Here we see that `sqrt2` is a rational number which is a contradiction as we know that `sqrt2` is an irrational number
Hence `6+sqrt2` is irrational.
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पाठ 1: Real Numbers - EXERCISE 1.5 [पृष्ठ १.३६]
