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Show that the Tangents to the Curve Y = 7x3 + 11 at the Points Where X = 2 and X = −2 Are Parallel. - Mathematics

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प्रश्न

Show that the tangents to the curve y = 7x3 + 11 at the points where x = 2 and x = −2 are parallel.

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उत्तर

The equation of the given curve is y = 7x3 + 11.

It is observed that the slopes of the tangents at the points where x = 2 and x = −2 are equal.

Hence, the two tangents are parallel.

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पाठ 6: Application of Derivatives - Exercise 6.3 [पृष्ठ २१२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 6 Application of Derivatives
Exercise 6.3 | Q 16 | पृष्ठ २१२

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