Advertisements
Advertisements
प्रश्न
Show that `(4/3 m - 3/4 n)^2 + 2mn = 16/9 m^2 + 9/16 n^2`
Advertisements
उत्तर
L.H.S = `(4/3 m - 3/4n)^2 + 2mn`
= `(4/3 m)^2 - 2(4/3 m)(3/4 n) + (3/4 n)^2 + 2mn`
= `16/9 m^2 - 2mn + 9/16 n^2 + 2mn`
= `16/9 m^2 + 9/16 n^2` = R.H.S
संबंधित प्रश्न
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 113 × 87
Find the following product: (p2 + 16) \[\left( p^2 - \frac{1}{4} \right)\]
Evaluate the following: 109 × 107
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
By using identity evaluate the following:
73 – 103 + 33
On dividing p(4p2 – 16) by 4p(p – 2), we get ______.
Simplify:
(3x + 2y)2 – (3x – 2y)2
Simplify:
(4.5a + 1.5b)2 + (4.5b + 1.5a)2
Expand the following, using suitable identities.
(2x + 9)(2x – 7)
Expand the following, using suitable identities.
(0.9p – 0.5q)2
