Advertisements
Advertisements
प्रश्न
Show that: \[\sqrt[3]{64 \times 729} = \sqrt[3]{64} \times \sqrt[3]{729}\]
Advertisements
उत्तर
LHS = \[\sqrt[3]{64 \times 729} = \sqrt[3]{4 \times 4 \times 4 \times 9 \times 9 \times 9} = \sqrt[3]{\left\{ 4 \times 4 \times 4 \right\} \times \left\{ 9 \times 9 \times 9 \right\}} = 4 \times 9 = 36\]
RHS = \[\sqrt[3]{64} \times \sqrt[3]{729} = \sqrt[3]{4 \times 4 \times 4} \times \sqrt[3]{9 \times 9 \times 9} = 4 \times 9 = 36\]
Because LHS is equal to RHS, the equation is true.
APPEARS IN
संबंधित प्रश्न
Find the cubes of the number 55 .
Which of the following is perfect cube?
1728
What happens to the cube of a number if the number is multiplied by 5?
By taking three different values of n verify the truth of the following statement:
If n leaves remainder 1 when divided by 3, then n3 also leaves 1 as remainder when divided by 3.
Find the cube root of the following natural number 1157625 .
Multiply 210125 by the smallest number so that the product is a perfect cube. Also, find out the cube root of the product.
Find the cube root of the following integer −2744000 .
Find the cube-root of 9261.
Find the cube-root of 8000.
The cube root of 250047 is 63
