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प्रश्न
Show that: \[\sqrt[3]{27} \times \sqrt[3]{64} = \sqrt[3]{27 \times 64}\]
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उत्तर
LHS = \[\sqrt[3]{27} \times \sqrt[3]{64} = \sqrt[3]{3 \times 3 \times 3} \times \sqrt[3]{4 \times 4 \times 4} = 3 \times 4 = 12\]
RHS = \[\sqrt[3]{27 \times 64} = \sqrt[3]{3 \times 3 \times 3 \times 4 \times 4 \times 4} = \sqrt[3]{\left\{ 3 \times 3 \times 3 \right\} \times \left\{ 4 \times 4 \times 4 \right\}} = 3 \times 4 = 12\]
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