मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power. Ion CIOX4− IOX4− BrOX4− Reduction potential EΘ/V EΘ = 1.19 V EΘ = 1.65V EΘ = 1.74 V

Advertisements
Advertisements

प्रश्न

Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.

Ion \[\ce{CIO^{-}_{4}}\] \[\ce{IO^{-}_{4}}\] \[\ce{BrO^{-}_{4}}\]
Reduction
potential EΘ/V
EΘ = 1.19 V EΘ = 1.65V EΘ = 1.74 V

पर्याय

  • \[\ce{ClO^{-}_{4} > IO^{-}_{4} > BrO^{-}_{4}}\]

  • \[\ce{IO^{-}_{4} > BrO^{-}_{4} > ClO^{-}_{4}}\]

  • \[\ce{BrO^{-}_{4} > IO^{-}_{4} > ClO^{-}_{4}}\]

  • \[\ce{BrO^{-}_{4} > CIO^{-}_{4} > IO^{-}_{4}}\]

MCQ
Advertisements

उत्तर

\[\ce{BrO^{-}_{4} > IO^{-}_{4} > ClO^{-}_{4}}\]

Explanation:

The ability of a substance to be decreased is known as its reduction potential. As the substance's reduction potential rises, so does its power to reduce. It signifies the chemical's oxidising power (the ability of the material to cause other substances to lose electrons, which is known as oxidising power) grows.

As a result, the oxidising power is listed in decreasing order.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ ९४]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 7 The p-block Elements
Multiple Choice Questions (Type - I) | Q 26 | पृष्ठ ९४

संबंधित प्रश्‍न

Draw structure of Chlorine pentafluoride


Account for the following: Fluorine does not exhibit positive oxidation state.


Compare the oxidizing action of F2 and Cl2 by considering parameters such as bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy.


Account for the following :

Acidic character increases from HF to HI.


F2 has lower bond dissociation enthalpy than Cl2. Why?


Which halogen compound in the following pair will react faster in SN2 reaction CH3Br or CH3I.


Why are halogens coloured?


Arrange the following in the order of property indicated for the given set:

HF, HCl, HBr, HI - increasing acid strength.


Arrange the following in the decreasing order of their reducing character :

HF, HCl, HBr, HI


 Cl2 acts as a bleaching agent. 


Tincture of iodine is ____________.


Fluorine differs from the rest of the halogens in some of its properties. This is due to ____________.


Which is the strongest acid in the following:


Bond dissociation enthalpy of E–H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent?

Compound \[\ce{NH3}\] \[\ce{PH3}\] \[\ce{AsH3}\] \[\ce{SbH3}\]
Δdiss (E – H)/kJ mol–1 389 322 297 255

In solid state \[\ce{PCl5}\] is a ______.


Statement I: Acid strength increases in the order given as HF << HCl << HBr << HI.

Statement II: As the size of the elements F, Cl, Br, and I increase down the group, the bond strength of HF, HCl, HBr, and HI decreases and so the acid strength increases.

In the light of the above statements, choose the correct answer from the options given below.


Statement I: Acid strength increases in the order given as HF << HCl << HBr << HI.

Statement II: As the size of the elements F, Cl, Br, and I increase down the group, the bond strength of HF, HCl, HBr and HI decreases and so the acid strength increases.

In the light of the above statements, choose the correct answer from the options given below.


Give a reason for the following:

Mn+2 compounds are more stable than Fe+2 compounds.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×