Advertisements
Advertisements
प्रश्न
Radius of the 1st orbit of hydrogen atom is r0. What will be the radius of the 4th orbit?
Advertisements
उत्तर
`r α n^2`
`=> r_1/r_4 = 1^2/4^2`
`=> r_0/r_4 = 1/16`
⇒ r4 = 16 r0
The radius of the 4th orbit of a hydrogen atom is 16 times the radius of the 1st orbit.
APPEARS IN
संबंधित प्रश्न
With the help of a neat labelled diagram, describe the Geiger- Marsden experiment
The positively charged part of the atom possesses most of the mass in ______.
Answer the following question, which help you understand the difference between Thomson’s model and Rutherford’s model better.
In which model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of α-particles by a thin foil?
In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 80, when a α-particle of 8Mev energy impinges on it before it comes momentarily to rest and reverses its direction.
How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?
In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 75, when a α-particle of 5 MeV energy impinges on it before it comes momentarily to rest and reverses its direction.
How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?
As compared to 12C atom, 14C atom has ______.
In 88 Ra226 nucleus, there are
A narrow beam of protons, each having 4.1 MeV energy is approaching a sheet of lead (Z = 82). Calculate:
- the speed of a proton in the beam, and
- the distance of its closest approach
According to Bohr model, magnetic field at centre (at the nucleus) of a hydrogen atom due to motion of electron in the ninth orbit is proportional to:
When alpha particles are sent through a thin gold foil, most of them go straight through the foil, because ______.
