Advertisements
Advertisements
प्रश्न
Put three different numbers in the circles so that when you add the numbers at the end of each line you always get a perfect square.
Advertisements
उत्तर
6, 19 and 30 are the three numbers in which, when we add the end of each line we always get a perfect square.
6 + 19 = 25
6 + 30 = 36
19 + 30 = 49 
APPEARS IN
संबंधित प्रश्न
What will be the units digit of the square of the following number?
52
What will be the units digit of the square of the following number?
99880
Which of the following triplets are pythagorean?
(8, 15, 17)
Observe the following pattern \[1 = \frac{1}{2}\left\{ 1 \times \left( 1 + 1 \right) \right\}\]
\[ 1 + 2 = \frac{1}{2}\left\{ 2 \times \left( 2 + 1 \right) \right\}\]
\[ 1 + 2 + 3 = \frac{1}{2}\left\{ 3 \times \left( 3 + 1 \right) \right\}\]
\[1 + 2 + 3 + 4 = \frac{1}{2}\left\{ 4 \times \left( 4 + 1 \right) \right\}\]
and find the values of following:
1 + 2 + 3 + 4 + 5 + ... + 50
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
12 + 22 + 32 + 42 + ... + 102
Which of the following number square of even number?
373758
Find the square of the following number:
127
Find the square of the following number:
503
Find the square of the following number:
95
Write two Pythagorean triplets each having one of the numbers as 5.
