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प्रश्न
Puneet has a Recurring Deposit Account in the Bank of Baroda and deposits Rs. 140 per month for 4 years. If he gets Rs. 8,092 on maturity, find the rate of interest given by the bank.
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उत्तर
Installment per month (P) = Rs. 140
Number of months (n) = 48
Let rate of interest (r) = r % p.a.
∴ `S.I. = P xx (n(n + 1))/(2 xx 12) xx r/100`
= `140 xx (48(48 + 1))/(2xx 12) xx r/100`
= `140 xx 2352/24 xx r/100`
= Rs. (137.20)r
Maturity value = Rs. (140 × 48) + Rs. (137.20)r
Given maturity value = Rs. 8,092
Then Rs. (140 × 48) + Rs. (137.20)r = Rs. 8,092
⇒ 137.20r = Rs. 8,092 – Rs. 6,720
⇒ r = `1372/137.20` = 10%
संबंधित प्रश्न
Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets Rs. 1200 as interest at the time of maturity, find:
- the monthly instalment.
- the amount of maturity.
A page from the Savings Bank Account of Mr Prateek is given below:
| Date | Particulars | Withdrawal (In Rs.) |
Deposit (In Rs.) |
Balances (In Rs.) |
| January 1st, 2006 | B/F | - | - | 1270 |
| January 7th, 2006 | By Cheque | - | 2310 | 3580 |
| March 9th, 2006 | To Self | 2000 | - | 1580 |
| June 26th, 2006 | By Cash | - | 6200 | 7780 |
| June 10th 2006 | To Cheque | 4500 | - | 3280 |
| July 15th, 2006 | By Clearing | - | 2630 | 5910 |
| October 18th, 2006 | To Cheque | 530 | - | 5380 |
| October 27th, 2006 | To Self | 2690 | - | 2690 |
| November 3rd, 2006 | By Cash | - | 1500 | 4190 |
| December 6th, 2006 | To Cheque | 950 | - | 3240 |
| December 23rd, 2006 | By Transfer | - | 2920 | 6260 |
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