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प्रश्न
Ashish deposits a certain sum of money every month is a Recurring Deposit Account for a period of 12 months. If the bank pays interest at the rate of 11% p.a. and Ashish gets ₹ 12,715 as the maturity value of this account, what sum of money did money did he pay every month?
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उत्तर
Let Installment per month (P) = Rs. y
Number of months (n) = 12
Rate of interest (r) = 11% p.a
So,
∴ `S.I. = P xx (n(n + 1))/(2 xx 12) xx r/100`
= `y xx (12(12 + 1))/(2 xx 12) xx 11/100`
= `y xx 156/24 xx 11/100`
= Rs 0.715y
Hence,
Maturity value = Rs. (y × 12) + Rs. 0.715y = Rs. 12.715y
Given maturity value = Rs. 12,715
So, on equating we have
Rs. 12.715y = Rs 12,715
`\implies` y = `12715/12.715` = Rs. 1000
Therefore, the sum of money Ashish paid every month was Rs. 1000.
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संबंधित प्रश्न
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Deposit (Rs.) | Balance (Rs.) |
| April 3rd 2006 | B/F | 6000 | ||
| April 7th | By cash | 2300 | 8300 | |
| April 15th | By cheque | 3500 | 11800 | |
| May 20th | To self | 4200 | 7600 | |
| June 10th | By cash | 5800 | 13400 | |
| June 15th | To self | 3100 | 10300 | |
| August 13th | By cheque | 1000 | 11300 | |
| August 25th | To self | 7400 | 3900 | |
| September 6th 2006 |
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