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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Prove the following: 2cos2A+12cos2A-1 = tan(60° + A) tan(60° − A)

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प्रश्न

Prove the following:

`(2cos2"A" + 1)/(2cos2"A" - 1)` = tan(60° + A) tan(60° − A)

बेरीज
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उत्तर

R.H.S. = tan(60° + A) tan(60° − A)

= `(sin(60^circ + "A")sin(60^circ - "A"))/(cos(60^circ + "A")cos(60^circ - "A")`

= `(2sin(60^circ + "A")sin(60^circ - "A"))/(2cos(60^circ + "A")cos(60^circ - "A")`

= `(cos[60^circ + "A" - (60^circ - "A")] - cos(60^circ + "A" + 60^circ - "A"))/(cos(60^circ + "A" + 60^circ - "A") + cos[60^circ + "A" - (60^circ - "A")]`

= `(cos2"A" - cos120^circ)/(cos120^circ - cos2"A")`

= `(cos2"A" - cos(180^circ - 60^circ))/(cos(180^circ - 60^circ) + cos2"A")`

= `(cos2"A" - (- cos 60^circ))/(- cos60^circ + cos2"A")`

= `(cos2"A" + 1/2)/(-1/2 + cos2"A")`

= `(2cos2"A" + 1)/(2cos2"A" - 1)`

= L.H.S.

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पाठ 3: Trigonometry - 2 - Miscellaneous Exercise 3 [पृष्ठ ५७]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
पाठ 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q II. (13) | पृष्ठ ५७

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