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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Select the correct option from the given alternatives : If tan A – tan B = x and cot B – cot A = y, then cot (A – B) = _____ - Mathematics and Statistics

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प्रश्न

Select the correct option from the given alternatives :

If tan A – tan B = x and cot B – cot A = y, then cot (A – B) = _____

पर्याय

  • `1/y - 1/x`

  • `1/x - 1/y`

  • `1/x + 1/y`

  • `(xy)/(x - y)`

MCQ
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उत्तर

If tan A – tan B = x and cot B – cot A = y, then cot (A – B) = `1/x + 1/y`

Explanation:

x = `sin"A"/cos"A" - sin"B"/cos"B"`

= `(sin"A"cos"B" - cos"A"sin"B")/(cos"A"cos"B")`

= `(sin("A" - "B"))/(cos"A" cos"B")`

y = `cos"B"/sin"B" - cos"A"/sin"A"`

= `(sin"A" cos"B" - cos"A"sin"B")/(sin"A"sin"B")`

= `(sin("A"- "B"))/(sin"A"sin"B")`

∴ `y/x = (cos"A"cos"B")/(sin"A"sin"B")` = cot A cot B

cot (A – B) = `(cot"A" cot"B" + 1)/(cot "B" - cot "A")`

= `(y/x + 1)/y`

= `(x + y)/(xy)`

= `1/x + 1/y`

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Trigonometric Functions of Sum and Difference of Angles
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - 2 - Miscellaneous Exercise 3 [पृष्ठ ५६]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q I. (2) | पृष्ठ ५६

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