मराठी

Prove the following: ∫01sin-1xdx=π2-1 - Mathematics

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प्रश्न

Prove the following:

`int_0^1sin^(-1) xdx = pi/2 - 1`

बेरीज
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उत्तर

Let `I = int_0^1 sin^-1 x dx`

`= int_0^1 sin^-1 x * 1 dx`

Integrating by parts,

`= [sin^-1 x * x]_0^1 - int_0^1 1/sqrt(1 - x^2) * x  dx`

`= [x sin^-1 x]_0^1 + 1/2 int_0^1 (-2x)/sqrt(1 - x^2) dx`

`= {x sin^-1 x + 1/2 [(1 - x^2)^(1/2)/(1/2)]}_0^1`

`= [(sin^-1) + 1/2 xx 2/1 (0 - 1)]`

`= pi/2 - 1`

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पाठ 7: Integrals - Exercise 7.12 [पृष्ठ ३५३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.12 | Q 39 | पृष्ठ ३५३

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