मराठी

Prove the following: ∫0π2sin3xdx=23 - Mathematics

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प्रश्न

Prove the following:

`int_0^(pi/2) sin^3 xdx = 2/3`

बेरीज
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उत्तर

`= int_0^(pi/2) sin^3 x  dx`

`= 1/4 int_0^(pi/2) (3 sinx - sin 3x)  dx`        `....[∵ sin 3x = 3 sin x - 4 sin 3x]`

`= 1/4 [-3 cos  x + (cos 3x)/3]_0^(pi/2)`

`= 1/4 [- 3 cos  pi/2 + 1/3 cos  (3pi)/2] - 1/4 [- 3 cos 0 + (cos0)/3]`

`= 1/4 [0 + 0 + 3 - 1/3]`

`= 1/4 (8/3)`

`= 2/3`

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पाठ 7: Integrals - Exercise 7.12 [पृष्ठ ३५३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.12 | Q 37 | पृष्ठ ३५३

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