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Prove That: Tan 5 π 4 Cot 9 π 4 + Tan 17 π 4 Cot 15 π 4 = 0 - Mathematics

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प्रश्न

Prove that:

\[\tan\frac{5\pi}{4}\cot\frac{9\pi}{4} + \tan\frac{17\pi}{4}\cot\frac{15\pi}{4} = 0\]

 

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उत्तर

\[ \frac{5\pi}{4} = 225^\circ, \frac{9\pi}{4} = 405^\circ, \frac{17\pi}{4} = 765^\circ, \frac{15\pi}{4} = 675^\circ\]
LHS = \[\tan 225^\circ\cot 405^\circ + \tan 765^\circ \cot 675^\circ\]
\[ = \tan\left( 90^\circ \times 2 + 45^\circ \right)\cot\left( 90^\circ \times 4 + 45^\circ \right) + \tan\left( 90^\circ \times 8 + 45^\circ \right) \cot\left( 90^\circ \times 7 + 45^\circ \right) \]
\[ = \tan 45^\circ\cot 45^\circ + \tan 45^\circ \left[ - \tan45^\circ \right]\]
\[ = \tan 45^\circ\cot 45^\circ - \tan 45^\circ \tan 45^\circ\]
\[ = 1 \times 1 - 1 \times 1\]
\[ = 1 - 1\]
\[ = 0\]
 = RHS
Hence proved.

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पाठ 5: Trigonometric Functions - Exercise 5.3 [पृष्ठ ४०]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 5 Trigonometric Functions
Exercise 5.3 | Q 9.5 | पृष्ठ ४०

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