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प्रश्न
Prove that:
log10 125 = 3(1 - log102).
बेरीज
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उत्तर
3 (1 - log10 2)
⇒ 3 (log10 10 - log10 2)
⇒ 3 log10 ` ((10 ) / ( 2 )) `
⇒ 3 log10 5
⇒ log10 53
⇒ log10 125
Hence proved.
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Expansion of Expressions with the Help of Laws of Logarithm
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