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प्रश्न
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उत्तर
LHS = cos(570°) sin(510°) + sin(−330°) cos(−390°)
= cos(570°) sin(510°) + [−sin(330°)]cos(390°)
= cos(570°) sin(510°) −sin(330°)
= cos(90° × 6 + 30°) sin(90° × 5 + 60°) − sin(90° × 3 + 60°) cos(90° × 4 + 30°)
= − cos(30°) cos(60°) − [−cos(60°)] cos(30°)]
= − cos(30°) cos(60°) + cos(30°) sin(60°)
= 0
= RHS
Hence proved .
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