Advertisements
Advertisements
प्रश्न
Predict whether van’t Hoff factor, (i) is less than one or greater than one in the following:
CH3COOH dissolved in water
Advertisements
उत्तर
van't hoff factor i = `"total number of moles of particles after dissociation association"/"no.of moles of particls before association dissociation"`
(i) CH3COOH
\[\ce{CH3\underset{1}{C}OOH->[H2O]CH3\underset{1}{C}OO- \underset{+1 = 2}{+H+}\text{(dissociation)} }\]
`i = 2/1 =2 ` (i is greater 1)
(ii) CH3COOH dissolved in benzene
\[\ce {2C\underset{2}{H}3COOH ->[benzene]\underset{1\text{(due to H-bonding)}}{CH3COOH}2}\] (association)
1(due to H-bonding)
`i= 1/2=0.5` (i is less than 1)
APPEARS IN
संबंधित प्रश्न
Derive van’t Hoff general solution equation.
Define van’t Hoff factor.
Define the term Abnormal molar mass
How will you convert the following in not more than two steps:
Benzoic acid to Benzaldehyde
The freezing point depression constant for water is 1.86° K Kg mol-1. If 5 g Na2SO4 is dissolved in 45 g water, the depression in freezing point is 3.64°C. The Vant Hoff factor for Na2SO4 is ______.
Phenol dimerizes in benzene having van’t Hoff factor 0.54. What is the degree of association?
Maximum lowering of vapour pressure is observed in the case of ______.
A molecule M associates in a given solvent according to the equation \[\ce{M <=> (M)_n}\]. For a certain concentration of M, the van't Hoff factor was found to be 0.9 and the fraction of associated molecules was 0.2. The value of n is ______.
Why is the value of van't Hoff factor for ethanoic acid in benzene close to 0.5?
Why is boiling point of 1 M NaCl solution more than that of 1 M glucose solution?
