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प्रश्न
Population of a city in the years 2005 and 2010 are 1,35,000 and 1,45,000 respectively. Find the approximate population in the year 2015. (assuming that the growth of population is constant)
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उत्तर
Let us choose the year along the x-axis and the population of the city along the y-axis.
Given In the year 2005 population is 1,35,000
The corresponding point is (2005, 1,35,000)
In the year 2010, population is 1,45,000
The corresponding point is (2010, 1,45,000)
Let Y denote the year and P denote the population.
The relation connecting Y and P is the equation of the straight line joining the points (2005, 1,35,000) and (2010, 1,45,000)
`("Y" - 2005)/(2010 - 2005) = ("P" - 135000)/(1445000 - 135 000)`
`("Y" - 2005)/5 = ("P" - 135000)/10000`
When y = 2015
2015 – 2005 = `("P" - 135000)/2000`
10 = `("P" - 135000)/2000`
P = 135000 + 10 × 2000
P = 135000 + 20000 = 155000
∴ The population in the year 2015 is 1,55,000
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