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Plane Microwaves Are Incident on a Long Slit of Width 5.0 Cm. Calculate the Wavelength of the Microwaves If the First Diffraction Minimum is Formed at θ = 30°.

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प्रश्न

Plane microwaves are incident on a long slit of width 5.0 cm. Calculate the wavelength of the microwaves if the first diffraction minimum is formed at θ = 30°.

बेरीज
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उत्तर

Given:-

Width of the slit, b = 5.0 cm

First diffraction minimum is formed at θ = 30°.

For the diffraction minima, we have

`bsinθ = nλ`

For the first minima, we put n = 1.

\[5 \times \sin30^\circ = 1 \times \lambda\]

\[ \Rightarrow \lambda = \frac{5}{2} = 2 . 5  cm\]

Therefore, the wavelength of the microwaves is 2.5 cm.

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पाठ 17: Light Waves - Exercise [पृष्ठ ३८३]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 17 Light Waves
Exercise | Q 39 | पृष्ठ ३८३

संबंधित प्रश्‍न

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(b) \[\nu_A  <  \nu_B  <  \nu_C\]

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(d) \[\nu_B  = \frac{1}{2}\left( \nu_A + \nu_C \right)\]


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(a) \[\nu_A  >  \nu_B  >  \nu_C\]

(b) \[\nu_A  <  \nu_B  <  \nu_C\]

(c) \[\nu_A  =  \nu_B  =  \nu_C\]

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Answer in brief:

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