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प्रश्न
Phase difference between a node and an adjacent antinode in a stationary wave is ______.
पर्याय
`pi/4` rad
`pi/2`rad
`(3pi)/4`rad
`pi` rad
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उत्तर
Phase difference between a node and an adjacent antinode in a stationary wave is `underlinebb(pi/2rad)`.
Explanation:
In a fixed wave, there is a phase difference of `π/2` `π/2` radians between a node (where there is no movement) and an antinode next to it (where there is maximum movement). This is because the node has no movement and the antinode has the most amplitude, which is equal to a quarter of the oscillation cycle or `π/2` `π/2` radians in phase.
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