Question

Perform a cross(es) where haemophilic daughter(s) and haemophilic son(s) are produced in same ratio.

Answer 1

Cross for equal production of haemophilic daughters and sons:

Let X^H = Normal allele

X^h = Haemophilia allele

Consider a cross between a carrier mother (X^HX^h) and a haemophilic father (X^hY)

Parental genotypes:	XHXh (Carrier female) × XhY (Haemophilic male)
Gametes:	XH, Xh, Xh, Y

Punnett Square:

	Xh	Y
XH	XHXh (Carrier Daughter)	XHY (Normal Son)
Xh	XhXh (Hemophilic Daughter)	XhY (Haemophilic Son)

Ratio - 1 Haemophilic Daughter : 1 Haemophilic Son