Advertisements
Advertisements
प्रश्न
Name the method used for preparation of the following salt from the list given below:
Zinc ion and Lead ion.
Advertisements
उत्तर
Zinc ion and Lead ion.
(i) \[\ce{ZnSO4 + 2NH4OH -> Zn(OH)2 v + (NH4)2SO4}\]
Zn(OH)2 forms white gelatinous precipitates. In the presence of excess of ammonium hydroxide these precipitates get dissolved.
(ii) \[\ce{Pb(NO3)2 + 2NH4OH -> Pb(OH)2 v + 2NH4NO3}\]
Pb(OH)2 forms white precipitates. This precipitate is insoluble in the presence of excess of ammonium hydroxide.
Concept Insight : Ammonium hydroxide forms insoluble hydroxides when treated with certain metallic salt solution. The insoluble hydroxides thus formed get precipitated in the form of a precipitate and may be identified by their distinct colours.
APPEARS IN
संबंधित प्रश्न
Choose the correct answer from the options given below:
A chloride which forms a precipitate that is soluble in excess of ammonium hydroxide is:
1) Calcium chloride
2) Ferrous chloride
3) Ferric chloride
4) Copper chloride
How will you distinguish NH4OH solution from NaOH solution?
Name the metal hydroxides which are insoluble in ammonium hydroxide solution.
Choose the correct answer from the options given below :
Which salt solution is soluble in excess of NH4OH
Distinguish between the following pair of compound using the test given within bracket.
Iron (II) Sulpate an and iron(III) using ammonium hydroxide)
State what do you observe when ammonium hydroxide to Iron (III) sulphate solution.
What would you observe in the following cases:
Ammonium hydroxide is first added in a small quantity and then in excess to a solution of copper sulphate.
Write balanced equation copper sulphate solution with ammonium hydroxide solution.
Write a balanced equation:
Copper sulphate solution with ammonium hydroxide solution.
Write a balanced equation:
Copper sulphate solution with ammonium hydroxide solution.
