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प्रश्न
Moment of force = force × perpendicular distance of force – from the pivoted point.
पर्याय
True
False
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उत्तर
True.
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संबंधित प्रश्न
A half metre rod is pivoted at the centre with two weights of 20gf and 12gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.
1) Which of the two forces acting on the rigid rod causes clockwise moment?
2) Is the rod in equilibrium?
3) The direction of 20 kgf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?
State the S.I. unit of moment of force.
What are non-contact forces? Give two example
State Newton's Second law of motion. Under what conditon does it take the form F = ma?
Name of S.I. unit of momentum.
State two factor on which moment of force about a point depends.
It is easier to turn the steering wheel of a large diameter than that of a small diameter. Given reason.
The diagram in the figure shows a uniform metre rule weighing 100 gf, pivoted as its centre O. two weight 150 gf and 250 gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm . Calculate
the total anticlockwise moment about o.
Classify the following amongst contact and non-contact forces.
normal reaction force,
Calculate the minimum distance between point of application of force and axis of rotation of a rigid body, if a force 125 N produces a moment of force of 25.75 Nm.
