मराठी

Mark the Correct Alternative in the Following Question: for the Following Probability Distribution: X: 1 2 3 4 P(X): 1 10 1 5 3 10 2 5 the Value of E(X2) is - Mathematics

Advertisements
Advertisements

प्रश्न

Mark the correct alternative in the following question:

For the following probability distribution:
 

X : 1 2 3 4
P(X) :
 

\[\frac{1}{10}\]
 

\[\frac{1}{5}\]
 

\[\frac{3}{10}\]
 

\[\frac{2}{5}\]


The value of E(X2) is

पर्याय

  • 3     

  •  5   

  •  7   

  •  10

MCQ
बेरीज
Advertisements

उत्तर

The probability distribution of X is given below:

X : 1 2 3 4
P(X) :
 

\[\frac{1}{10}\]
 

\[\frac{1}{5}\]
 

\[\frac{3}{10}\]
 

\[\frac{2}{5}\]

\[E\left( X^2 \right) = 1^2 \times \frac{1}{10} + 2^2 \times \frac{1}{5} + 3^2 \times \frac{3}{10} + 4^2 \times \frac{2}{5}\]
\[ = \frac{1}{10} + \frac{8}{10} + \frac{27}{10} + \frac{64}{10}\]
\[ = \frac{100}{10}\]
\[ = 10\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 32: Mean and Variance of a Random Variable - MCQ [पृष्ठ ४७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 32 Mean and Variance of a Random Variable
MCQ | Q 8 | पृष्ठ ४७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×