मराठी

Lim X → 2 X − 2 √ X − √ 2 - Mathematics

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प्रश्न

\[\lim_{x \to 2} \frac{x - 2}{\sqrt{x} - \sqrt{2}}\] 

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उत्तर

\[\lim_{x \to 2} \left[ \frac{x - 2}{\sqrt{x} - \sqrt{2}} \right]\] It is of the form \[\frac{0}{0}\] 

⇒ \[\lim_{x \to 2} \left[ \frac{\left( \sqrt{x} \right)^2 - \left( \sqrt{2} \right)^2}{x - \sqrt{2}} \right]\] 

= \[\lim_{x \to 2} \left[ \frac{\left( \sqrt{x} - \sqrt{2} \right)\left( \sqrt{x} + \sqrt{2} \right)}{\left( x - \sqrt{2} \right)} \right]\]

=  \[\sqrt{2} + \sqrt{2}\] 

= \[2\sqrt{2}\]

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पाठ 29: Limits - Exercise 29.4 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 29 Limits
Exercise 29.4 | Q 14 | पृष्ठ २८

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