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lim x → 2 √ 3 − x − 1 2 − x - Mathematics

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प्रश्न

\[\lim_{x \to 2} \frac{\sqrt{3 - x} - 1}{2 - x}\] 

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उत्तर

\[\lim_{x \to 2} \left[ \frac{\sqrt{3 - x} - 1}{2 - x} \right]\] It is of the form \[\frac{0}{0} .\]Rationalising the numerator: 

\[\lim_{x \to 2} \left[ \frac{\left( \sqrt{3 - x} - 1 \right)\left( \sqrt{3 - x} + 1 \right)}{\left( 2 - x \right)\left( \sqrt{3 - x} + 1 \right)} \right]\] 

\[= \lim_{x \to 2} \left[ \frac{3 - x - 1}{\left( 2 - x \right)\left( \sqrt{3 - x} + 1 \right)} \right]\]

\[= \lim_{x \to 2} \left[ \frac{\left( 2 - x \right)}{\left( 2 - x \right)\left( \sqrt{3 - x} + 1 \right)} \right]\] 

\[= \frac{1}{\sqrt{3 - 2} + 1}\]
\[ = \frac{1}{1 + 1}\]
\[ = \frac{1}{2}\] 

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पाठ 29: Limits - Exercise 29.4 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 29 Limits
Exercise 29.4 | Q 5 | पृष्ठ २८

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