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प्रश्न
\[\lim_{x \to 0} \frac{\sin x^0}{x}\]
पर्याय
1
π
x
π/180
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उत्तर
(d) \[\frac{\pi}{180}\]
\[\lim_{x \to 0} \frac{\sin x^0}{x}\]
\[ = \lim_{x \to 0} \frac{\sin \frac{\pi}{180}x}{x}\]
\[ = \lim_{x \to 0} \frac{\sin \left( \frac{\pi}{180}x \right)}{\left( \frac{\pi}{180}x \right)} \times \frac{\pi}{180}\]
\[ = \frac{\pi}{180} \times 1 = \frac{\pi}{180}\]
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