Question

Let M and N be two events such that P(M) = 0.6, P(N) = 0.2 and P(MN) = 0.5, then P(M'/N') is ______.

पर्याय

• `7/8`

• `1/2`

• `2/5`

• `2/3`

Answer 1

Let M and N be two events such that P(M) = 0.6, P(N) = 0.2 and P(MN) = 0.5, then P(M'/N') is `bbunderline(7/8)`.

Explanation:

Given P(M) = 0.6, P(N) = 0.2

P(MN) = 0.5

`P((M')/(N')) = (P(M'∩N'))/(P(N'))`

= `(1 - P(M ∪ N))/(1 - P(N))`

= `(1 - [P(M) + P(N) - P(M∩N)])/(1 - P(N))`

= `(1 - [0.6 + 0.2 - 0.5])/(1 - 0.2)`

= `(1 - [0.3])/0.8`

= `0.7/0.8`

= `7/8`