Question

जर sec θ = `25/7`, तर tan θ ची किंमत काढा.

उकल:

1 + tan² θ = `square`

∴ 1 + tan² θ = `square`²

∴ tan² θ = `625/49` − `square`

= `(625 - 49)/49`

tan² θ = `576/49`

tan θ = `square`

Answer 1

1 + tan² θ = \[\boxed{sec^2 θ}\]

∴ 1 + tan² θ =\[\boxed{\left(\frac{25}7\right)^2}\] 

∴ tan² θ = `625/49` − \[\boxed{1}\]

= `(625 - 49)/49`

tan² θ = `576/49`

tan θ = \[\boxed{\frac{24}7}\]