मराठी

In the given figure, O is the centre of the circle. ∠DAE = 70°. With giving suitable reasons find the measure of: (i) ∠BCD (ii) ∠BOD (iii) ∠OBD - Mathematics

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प्रश्न

In the figure given, O is the centre of the circle. ∠DAE = 70°. Find giving suitable reasons, the measure of:

  1. ∠BCD
  2. ∠BOD
  3. ∠OBD

In the given figure, O is the centre of the circle. ∠DAE = 70°. With giving suitable reasons find the measure of:

  1. ∠BCD 
  2. ∠BOD 
  3. ∠OBD

बेरीज
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उत्तर

i. ∠DAE = 70°  ...(Given)

∠BAD + ∠DAE = 180° ...(Linear pair)

⇒ ∠BAD + 70° = 180°

⇒ ∠BAD = 110°

Since ABCD is a cyclic quadrilateral, sum of the measures of the opposite angles are supplementary.

So, ∠BCD + ∠BAD = 180°

⇒ ∠BCD + 110° = 180°

⇒ ∠BCD = 70°

ii. ∠BOD = 2∠BCD  ...(Inscribed angle theorem)

⇒ ∠BOD = 2(70°) = 140°

iii. In ΔOBD

OB = OD  ...(Radii of same circle)

⇒ ∠OBD = ∠ODB

By angle sum property,

∠OBD + ∠ODB + ∠BOD = 180°

⇒ 2∠OBD + ∠BOD = 180°

⇒ 2∠OBD + 140° = 180°

⇒ 2∠OBD = 40°

⇒ ∠OBD = 20°

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पाठ 15: Circles - Exercise 15A [पृष्ठ ३३२]

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नूतन Mathematics [English] Class 10 ICSE
पाठ 15 Circles
Exercise 15A | Q 20. | पृष्ठ ३३२
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