मराठी

In the given figure, ‘O’ is the centre of the circle and AE = ED. If ∠ABC = 110° then ∠CBD is equal to ______. - Mathematics

Advertisements
Advertisements

प्रश्न

In the given figure, ‘O’ is the centre of the circle and AE = ED. If ∠ABC = 110° then ∠CBD is equal to ______.

पर्याय

  • 20°

  • 30°

  • 40°

  • 55°

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

In the given figure, ‘O’ is the centre of the circle and AE = ED. If ∠ABC = 110° then ∠CBD is equal to 20°.

Explanation:

∠ABC = 110° subtends arc ADC. Since AE = ED, point E divides arc AD into two equal arcs, so arc AE = arc ED.

Thus, the angle subtended by half of arc AD at point C gives ∠CBD = 20°.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Circles - Exercise 15C [पृष्ठ ३५९]

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
पाठ 15 Circles
Exercise 15C | Q 10. | पृष्ठ ३५९
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×