मराठी

In the given figure, O is centre of the circle and ∠B = 55°. The angle A is equal to ______.

Advertisements
Advertisements

प्रश्न

In the given figure, O is centre of the circle and \[\angle \mathrm{B}=55^{\circ}\]. The angle A is equal to ______.

The image displays a circle with a diameter AB passing through the center O, point C on the circumference, radii, and an angle of $55^\circ$. It illustrates circle geometry problems involving isosceles triangles formed by radii and inscribed angle relationships.

पर्याय

  • 55°

  • 35°

  • 45°

  • 50°

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

In the given figure, O is centre of the circle and \[\angle \mathrm{B}=55^{\circ}\]. The angle A is equal to 35°.

Explanation: 

From figure,

In △ OCB,

OB = OC (Radius of common circle)

We know that,

Angles opposite to equal sides of a triangle are equal.

∴ ∠C = ∠B = 55°

By angle sum property of triangle,

⇒ ∠C + ∠B + ∠O = 180°

⇒ 55° + 55° + ∠O = 180°

⇒ ∠O + 110° = 180°

⇒ ∠O = 180° - 110° = 70°.

We know that,

The angle which an arc subtends at the center is double that which it subtends at any point on the remaining part of the circumference.

⇒ ∠O = 2∠A

⇒ ∠A = `(∠O)/2 = (70°)/2`​ = 35°

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 17: Circles - EXERCISE 17 (A) [पृष्ठ २५७]

APPEARS IN

सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 17 Circles
EXERCISE 17 (A) | Q 1. (a) | पृष्ठ २५७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×